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![sin[pi/6+cos^(- 1)(-(sqrt(3))/2)]=` - YouTube](https://i.ytimg.com/vi/hAtJRyfcGwo/maxresdefault.jpg "sin[pi/6+cos^(- 1)(-(sqrt(3))/2)]=` - YouTube")
sin[pi/6+cos^(- 1)(-(sqrt(3))/2)]=` - YouTube
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![How do you calculate\\[\\arccos \\left( { - \\dfrac{{\\sqrt 3 }}{2}} \\right)\\]?](https://www.vedantu.com/question-sets/9f966392-7488-4f46-90f7-a26bf13fc0d22105975331587852969.png "How do you calculate\\[\\arccos \\left( { - \\dfrac{{\\sqrt 3 }}{2}} \\right)\\]?")
How do you calculate\\[\\arccos \\left( { - \\dfrac{{\\sqrt 3 }}{2}} \\right)\\]?
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If you get a maths question asking you to convert 3/pi radians into degree measure? Which value of pi will you take 3.142 or 180° In its solution 3/pi ×180°/pi…will the pi^2
SOLVED: Evaluate arccos a. in radians b. in degrees 2. Evaluate arctan in radians b. in degrees Evaluate arcsin in radians b. in degrees Evaluate arccos in radians b. in degrees
